Comments on: Count number of words in a MySQL column

By: F Laszlo

F Laszlo — Fri, 18 Nov 2011 19:18:37 +0000

Well, even if “column be empty” it works fine for me. Shows “0″.

By: mhehm

mhehm — Sat, 12 Nov 2011 07:22:36 +0000

if column be empty, it show 1 and it is not correct

By: Mihai Vinatoru

Mihai Vinatoru — Tue, 01 Nov 2011 12:14:50 +0000

Great. Thank you for this code snippet. You saved my day

By: F Laszlo

F Laszlo — Wed, 08 Jun 2011 14:38:19 +0000

Well done!
I’ve got inspiration and implemented this:

select round((LENGTH(name) – LENGTH(REPLACE(name, ‘word’, ”))) /length(‘word’))
from table;

This count only words ‘word’.

By: Imane

Imane — Fri, 22 Jan 2010 18:39:46 +0000

GREAT tip, i am trying to use this select statement to show all the words and sort them by number of occurence (how many times that occur). Any help on this would be GREATLY appreciated.

Thanks again

By: cormac

cormac — Thu, 20 Aug 2009 20:53:32 +0000

Has anyony managed an SQL query that will county the freuquency of words in column of a table?

By: Al

Al — Fri, 22 May 2009 05:15:45 +0000

That’s bloody awesome – very nice thinking outside of the box. Works a treat! Many thanks saves me bring everything in and doing it with php!

By: Ajay Arjunan

Ajay Arjunan — Tue, 12 May 2009 11:44:08 +0000

Great !!! Thanks for this query.

By: BL

BL — Mon, 04 May 2009 11:31:43 +0000

The real solution is to replace double or more spaces in the first LENGTH():

SELECT SUM( LENGTH(REPLACE(REPLACE(name,’ ‘,’ ‘),’ ‘,’ ‘)) – LENGTH(REPLACE(name, ‘ ‘, ”))+1)
FROM table;

Replacing double or more spaces in the second LENGTH() won’t modify the result, because it has the same effect as the first solution has: all spaces are removed from text.

By: Knut Urdalen

Knut Urdalen — Fri, 24 Apr 2009 07:03:19 +0000

Very nice Wasif It saved my day! Thanks!