Comments on: Saving images in MySQL with PHP

By: Wasif

Wasif — Tue, 29 Dec 2009 01:35:51 +0000

You need a single file like showimage.php and just need to pass the image id as I did in the example id=1
$query = “SELECT image from images where id=1″;

By: dark_byte

dark_byte — Sat, 26 Dec 2009 13:36:19 +0000

Hi nice article but what if I want to take multiple images form the database and display them.
Will I have to build a script for each image; please I badly need help over this.

By: 4ward.NRGie

4ward.NRGie — Wed, 11 Nov 2009 06:56:59 +0000

Here is my showimage.php
[code]

[code]
But I can't olad it ti index.php

By: roni08

roni08 — Thu, 30 Jul 2009 05:23:40 +0000

can anyone could help me with the fix image size, to display not necessarily damaging the resolution of the image?. it’s all about the code above. pls. help me. thanks.

By: roni08

roni08 — Wed, 29 Jul 2009 04:10:34 +0000

i’ve tried your provided code and it’s great and work properly. But my question is how do i resize the images or picture that i’ve been upload and save to my database. when i’m going to display the images/picture it has been cut. i hope you could help me. thanks.

By: Rusty777

Rusty777 — Thu, 23 Jul 2009 04:30:53 +0000

The code you provided worked great. I wish I had posted the problem a week ago. But I’m sure all the reading I did this week before I got desperate will pay off later. Thank you so much.

By: Wasif

Wasif — Wed, 22 Jul 2009 16:51:12 +0000

You just need to pass the $logo variable (I assume $logo contains the location of the image file) ’>

If you still have confusion, then post your code to review.

By: Rusty777

Rusty777 — Wed, 22 Jul 2009 16:20:42 +0000

Your “tag” did not show up but my graphics/logos are stored as files on the server. The NAME of each graphic is stored in a record in a mysql table which has the member data including the name of their logo, not the picture file, just the name of the file.

I have a bunch of members and need a way to pass the filename stored in mysql table to the “img src” statement in html.

In php, I have been successful in getting the name of the file into a variable ($logo) but have not found a way to use the variable in the “img src” statement.

The $logo var contains marie.jpg but HTML does not resolve the variable name. It just shows a broken image/link on the screen.

I hope this makes sense…

Thanks again.

By: Wasif

Wasif — Wed, 22 Jul 2009 13:45:42 +0000

Where did you store the graphic, in database or on the disk? If you have stored the graphic on disk, you can simply pass the path to the graphic/logo in tag like below

By: Rusty777

Rusty777 — Tue, 21 Jul 2009 14:36:29 +0000

Hello,

I am new to php and mysql… Fairly proficient in HTML

My situation is:
I have a mysql table with member info and a field named graphic1. The variable graphic1 contains the member’s logo/graphic.

I am able to use mysql_query and fetch_array to echo the filename of the member’s graphic but I need to display the actual graphic, not just the filename of the graphic.

Is it possible to pass the contents of variable “graphic1″, (i.e.this is the file’s name on my server) so I can use it in an html “img src=” statement.

Thanx for any assistance with this…